calculate number of atoms of the constituent element 52g of CO3
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divide it by its molar mass do it by uourself u get better result
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53 g of Na2CO3 Contain = 53106=12 mol.
No of atoms of Na = 12×2×6.022×1023= 6.022×1023.
No of atoms of C = 12×6.022×1023.
No of atoms of O = 12×3×6.022×1023= 9.033×1023
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