Question

calculate number of atoms of the constituent element in 53g of Na2CO3​

Answer 1

Answer:

=> 53 g of Na2CO3 Contain = 53106=12 mol.

=> No of atoms of Na = 12×2×6.022×1023= 6.022×1023.

=> No of atoms of C = 12×6.022×1023.

=> No of atoms of O = 12×3×6.022×1023= 9.033×1023.

Explanation:

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