Question

calculate number of atoms present in 1.80 grams of C6 h12 o6

Answer 1

Explanation:

Molecular weight of glucose is 180gm/mole

Why 180 gm/mole?

Because, Molecular formula of glucose is C6H12O6 .

Therfore, Molecular Mass =6C+12H+6O

=6(12)+12(1)+6(16)

=180gm/mole

Thus, 1.8gm glucose means it is 1.8/180=0.01 mole glucose..

Now, Molecular formula of glucose is C6H12O6 .. Thus 1 mole glucose contains 6 moles of oxygen atoms..

Thus, 0.01 mole glucose contains 0.06 moles of oxygen...

Now, 1 mole oxygen means it contains 6.022×1023 ...

Therefore, 0.06 mole oxygen means it contains 0.06×6.022×1023 atoms..

Thus, number of oxygen atoms is 3.6132×1022

Answer 2

Explanation:

Gram molecular wt of C6H12O6 = 180 g

180g of C6H12O6 contains _____ 6×10^23 atoms

1.8 g contains ___________ 1.8×6×10^23/ 180

= 6×10^23/100

= 6×10^21 atoms

so no of atoms = 6×10^21