Question

calculate number of atoms present in 11.5 liters of H2 at NTP

Answer 1

· So, 11.5 L of H2 = (1/22.4 ) x 11.5 mole = 0.51 moles of H2 gas. Since, 1 mole of H2 = 6.022 x 1023 molecules of H2 = 2 x 6.022 x 1023 atoms of H2. Hence, 0.51 ...

Answer 2

Answer:

We know that, at standard temperature and pressure, 1 mole of any gas at STP contains 22.4 L of it.

1 mole of Mercury(Hg) at STP = 22.4L

Therefore 11.5 liters of hydrogen(H2) is (1/22.4)*11.5 moles  = 0.51 moles of hydrogen gas.

We know that in 1 mole there is 6.022 × 10^23 molecules.

Hence,  for  0.51 moles of Hydrogen =0.51*[6.022 × 10^23] molecules of Hydrogen gas.

As there are 1 atoms in 2 molecule of Hydrogen(H2).  

Thus no. of atoms of mercury =2x3.071x 10 ^23 atoms=6.14 x 1023 atoms of H2.