Question

Calculate number of atoms present in 18g of glucose(C6H1206)



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Answer 1

Answer:

14.4 × 10^23

Explanation:

180 g of glucose contains 6.022 × 10^23 × 24 atoms

then,

18 g glucose will contain 6.022 × 10^23 × 24 / 180

= 14.4 × 10^23

24 atoms are present in 1 molecule of glucose

6 of Carbon

6 of Oxygen

and 12 of Hydrogen

that's why, total no. of atoms =6+6+12=24