Calculate number of atoms present in 2g of he
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Answer:
2g of helium contains 3 × 10²³ Atoms.
Explanation:
1 mole ( 6 × 10²³ atoms) of helium has 4 gram approximately.
So when there is 2 gram of helium it must contain half the atoms in 1 mole.
i.e 2g of helium = ( 6 × 10²³) ÷ 2
= 3 × 10²³ Atoms.
I hope it helps you
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