Calculate number of atoms present in 56Lof He at STP.
a) 24.0 92x10^23 B)12.046×10^23 C) 15.0575×10^23 D)6.023×10^23
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Answer is (C)..i.e. 15.05 ×10^23...
As 22.4L of he has NA atoms.
Therefore 56 L will have 15.05×10^23 atoms.
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