Question

calculate number of atoms present in 8 g of iron

Answer 1

Answer:

Here is your answer mate

Explanation:

0.860×1023 atoms of iron are present in 8 grams of iron metal.

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23}6.023×1023 of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{8g}{56g/mol}=0.14molesNumber of moles=Molar massGiven mass=56g/mol8g=0.14moles

1 mole of iron (Fe)(Fe) contains = 6.023\times 10^{23}6.023×1023 atoms of iron

0.14 mole of iron (Fe)(Fe) contain= \frac{6.023\times 10^{23}}{1}\times 0.14=0.860\times 10^{23}16.023×1023×0.14=0.860×1023 atoms of iron.

Answer 2

Explanation:

1 MOLE OF IRON =

$6.022 \times 10^{23}$

AND 1 mole of iron = 26g of Iron

then'

$6.022 \times 10^{-23}$

= 12 g of iron so 1g = 6.022*10^23/12

8g = 6.022*10^-23/12 *8