Question

calculate number of chloride ions present in 0.5 mole of ngcl2​

Answer 1

Explanation:

Step 1: Write out the chemical formula of the compound.

Magnesium Chloride = MgCl_2

Step 2: Convert moles into number of compounds using Avogadro's number

"0.5 moles" MgCl_2*((6.022*10^23)/("1 mole" MgCl_2))=3.011*10^23

Step 3: Determine how many Chloride ions there will be in 1 compound

There will be 2 Cl^(-) ions in each compound (Cl_2 part)

Step 4: Multiply the number from Step 2 by the number in Step 3

3.011*10^23*2=6.022*10^23

We do this because the ratio is 2 Cl^(-) ions for every 1 compound.

In the case of finding how many ions in general (both sodium and chloride), we would multiply by 3 because there are 3 ions per 1 compound.

Step 5: All done!

I hope this helped!

Answer 2

Answer:

1 mole will have Avogadro no.of molecules

$</strong><strong>N</strong><strong> </strong><strong>A</strong><strong> = 6.023 \times {10}^{23}$

For 0.5 moles

$no.of \: molecules = 6.023 \times {10}^{23} \times 0.5 = 3.011 \times {10}^{23}$

There are

$</strong><strong>2C</strong><strong> {l}^{ - }$

ions In each compound

So number of chloride ions present in 0.5 mole of Mgcl2

$2 \times 3.011 \times {10}^{23} = 6.023 \times {10}^{23}$

=Avagadro number =N A