Calculate number of electrons present in 1.4 grams of Nitrogen gas.
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broo ur very lucky i did this question till now is the question of some basic concept of chemistry...Number of moles in the given weight of Nitrogen gas.
Number of moles = Given weight/molecular weight
= 1.4/28
=0.05 moles
1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules.
0.05 moles of Nitrogen contains = 0.05*6.023*1023....i hope it will help u
= 3.011*1022 molecules
1 molecule of Nitrogen contains 14 electrons
3.011*1022 molecules contains = 3.011*1022*14
= 42.154*1022
= 4.215*1023 number of electrons....
Number of moles = Given weight/molecular weight
= 1.4/28
=0.05 moles
1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules.
0.05 moles of Nitrogen contains = 0.05*6.023*1023....i hope it will help u
= 3.011*1022 molecules
1 molecule of Nitrogen contains 14 electrons
3.011*1022 molecules contains = 3.011*1022*14
= 42.154*1022
= 4.215*1023 number of electrons....
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