Chemistry, asked by harshithaalgote, 1 month ago

calculate number of electrons present in 310gm of calcium phosphate (Ca3(PO4)2

Answers

Answered by jaswasri2006

0

Ca3 = 20(3)

P2 = 30(2)

O8 = 16(8)

= 120 + 128 = 248 electrons

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