Chemistry, asked by A1s2d2d4, 1 year ago

Calculate number of electrons present in 9.5 gram of phosphate (PO4)

Answers

Answered by Shivam011
0

Molar mass of PO4 = 95g/mol

therefore 95g of PO4 contain 6.022*10^23 atoms

1g of PO4 will contain 6.022*10^23/95 atoms

Hence 9.5g of PO4 will contain 6.022*10^22 atoms

Since 1 molecule contain 5+4(6) electrons

therefore total electrons =29*6.022*10^22 e

Answered by nany39
3
Number of electrons in 9.5 g of phosphate

According to formula

molar mass=95

9.5/95

=0.1

1 mole contains =6*10^22 ions

but each ion has 50 electrons

15+32+3

Total electrons in 9.5 gram in phosphate is =(6*10^22)*50

=3*10^24 in (PO4)3




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