Question

Calculate number of electrons, protons and

neutrons of following
I) 0.5 mol of Na+

please give me correct answer ​

Answer 1

Answer :-

→ Number of electrons = 3.011 × 10²⁴

→ Number of protons = 3.3121 × 10²⁴

→ Number of neutrons = 3.6132 × 10²⁴

Explanation :-

Firstly, let's calculate the number of ions in 0.5 mole of Na⁺.

= No of mole × Avogadro Number

= 0.5 × 6.022 × 10²³

= 3.011 × 10²³ ions

For electrons :-

Number of electrons in 1 ion of Na⁺ = 10

So, required number of electrons :-

= 10 × 3.011 × 10²³

= 30.11 × 10²³

= 3.011 × 10²⁴

For protons :-

Number of protons in 1 ion of Na⁺ = 11

So, required number of protons :-

= 11 × 3.011 × 10²³

= 33.121 × 10²³

= 3.3121 × 10²⁴

For neutrons :-

Number of neutrons in 1 ion of Na⁺ = 12

So, required number of neutrons :-

= 12 × 3.011 × 10²³

= 36.132 × 10²³

= 3.6132 × 10²⁴

Answer 2

Answer:

Given :-

• 0.5 mol of Na+

To Find :-

• Number of electrons, protons and neutrons.

Formula Used :-

$\clubsuit$ Number of Particles Formula :

$\longmapsto \sf\boxed{\bold{\pink{Number\: Of\: Particles =\: n \times 6.022 \times 10^{23}}}}$

where,

• n = Number of Moles

Solution :-

First, we have to find the number of particles :

Given :

• Number of Moles = 0.5 mol

According to the question by using the formula we get,

$\implies \sf Number\: of\: particles =\: 0.5 \times 6.022 \times 10^{23}$

$\implies \sf Number\: of\: particles =\: \dfrac{5}{10} \times \dfrac{6022}{1000} \times 10^{23}$

$\implies \sf Number\: of\: particles =\: \dfrac{30110}{10000} \times 10^{23}$

$\implies \sf\bold{\purple{Number\: of\: particles =\: 3.011 \times 10^{23}}}$

$\therefore$ The number of particles is 3.011 × 10²³.

Now, we have to find the number of electrons, protons and neutrons :

${\normalsize{\bold{\green{\underline{\bigstar\: Number\: of\: electrons\: :-}}}}}$

As we know that :

$\bigstar$ Number of electrons of Na+ is 10.

So,

$\longrightarrow \sf Number\: of\: electrons =\: 10 \times 3.011 \times 10^{23}$

$\longrightarrow \sf Number\: of\: electrons =\: 10 \times \dfrac{3011}{1000} \times 10^{23}$

$\longrightarrow \sf Number\: of\: electrons =\: \dfrac{30110}{1000} \times 10^{23}$

$\longrightarrow \sf Number\: of\: electrons =\: 30.11 \times 10^{23}$

$\longrightarrow \sf\bold{\red{Number\: of\: electrons =\: 3.011 \times 10^{24}}}$

$\therefore$ The number of electrons is 3.011 × 10²⁴.

__________________________________

${\normalsize{\bold{\green{\underline{\bigstar\: Number\: of\: protons\: :-}}}}}$

As we know that :

$\bigstar$ Number of protons of Na+ is 11.

So,

$\longrightarrow \sf Number\: of\: protons =\: 11 \times 3.011 \times 10^{23}$

$\longrightarrow \sf Number\: of\: protons =\: 11 \times \dfrac{3011}{1000} \times 10^{23}$

$\longrightarrow \sf Number\: of\: protons =\: \dfrac{33121}{1000} \times 10^{23}$

$\longrightarrow \sf Number\: of\: protons =\: 33.121 \times 10^{23}$

$\longrightarrow \sf \bold{\red{Number\: of\: protons =\: 3.3121 \times 10^{24}}}$

$\therefore$ The number of protons is 3.3121 × 10²⁴.

__________________________________

${\normalsize{\bold{\green{\underline{\bigstar\: Number\: of\: neutrons\: :-}}}}}$

As we know that :

$\bigstar$ Number of neutrons of Na+ is 12.

So,

$\longrightarrow \sf Number\: of\: neutrons =\: 12 \times 3.011 \times 10^{23}$

$\longrightarrow \sf Number\: of\: neutrons =\: 12 \times \dfrac{3011}{1000} \times 10^{23}$

$\longrightarrow \sf Number\: of\: neutrons =\: \dfrac{36132}{1000} \times 10^{23}$

$\longrightarrow \sf Number\: of\: neutrons =\: 36.132 \times 10^{23}$

$\longrightarrow \sf\bold{\red{Number\: of\: neutrons =\: 3.6132 \times 10^{24}}}$

$\therefore$ The number of neutrons is 3.6132 × 10²⁴.