calculate number of gm-atoms of oxygen in 3.15 gm of nitric acid.
vanah1:
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Hello Dear.
Here is the answer---
Molar Mass of the Nitric Acid (HNO₃) = 63 g/mole.
Mass of the oxygen Present in the 1 mole of HNO₃ = 48 g.
Now,
∵ 63 g of the Nitric Acid contains 48 g of the oxygen.
∴ 1 g of the nitric acid contains 48/63 g of the oxygen.
∴ 3.15 g of the nitric acid contains 2.4 g of the Oxygen.
Now,
Molar Mass of one molecule of Oxygen = 32 grams.
∵ No. of g atoms of Oxygen = Mass/Molar Mass
= 2.4/32
= 0.075 grams atoms.
Thus, No. of g atoms of the Oxygen in 3.15 grams of the Nitric Acid is 0.075.
Hope it helps.
Here is the answer---
Molar Mass of the Nitric Acid (HNO₃) = 63 g/mole.
Mass of the oxygen Present in the 1 mole of HNO₃ = 48 g.
Now,
∵ 63 g of the Nitric Acid contains 48 g of the oxygen.
∴ 1 g of the nitric acid contains 48/63 g of the oxygen.
∴ 3.15 g of the nitric acid contains 2.4 g of the Oxygen.
Now,
Molar Mass of one molecule of Oxygen = 32 grams.
∵ No. of g atoms of Oxygen = Mass/Molar Mass
= 2.4/32
= 0.075 grams atoms.
Thus, No. of g atoms of the Oxygen in 3.15 grams of the Nitric Acid is 0.075.
Hope it helps.
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