Question

Calculate number of H-atoms in 9g of NH4^+

Answer 1

One mole of $NH_4$ weighs 18 gm.

Number of moles in 9 grams of $NH_4$ = $\frac{9}{18}$

Number of moles in 9 grams of $NH_4$ = 0.5 moles

One molecule of $NH_4$ contains 4 atoms of Hydrogen.

Total number of molecules of $NH_4$  in 0.5 moles =$\(0.5 \times 6.022 \times 10^2^3\)$

Total number of Hydrogen atoms in 9 gm of $NH_4$ =  $\(0.5 \times 6.022 \times 10^2^3 \times 4\)$

Number of H-atoms = $\(12.044 \times 10^2^3\)$