Chemistry, asked by rajrajput29040, 1 year ago

calculate number of if ion present in 5.85 g of sodium chloride​

Answers

Answered by ArigiThanmai
3

Answer:

1.2042×10^23

Explanation:

5.85 gm of NaCl=5.85/58.5=0.1 moles

Each NaCl particle is equivalent to one Na^+ one Cl^-

2 ions

total moles of ions =0.1×2=0.2 moles

no of ions=0.2×6.022×10^23=1.2042×10^23.

.

=

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