Question

calculate number of milli equivalents of acid present in 50ml of 0.1 M sulphuric acid solution. ​

Answer 1

Volume of Acid =50ml

Molarity = 0.1M

Molar mass of Sulfuric Acid = 98 Grams

We know that:-

Molarity= Number of moles of solute/volume of solution(in litres)

Thus:-

Number of moles of solute = molarity * volume(in L)

Number of moles of sulfuric acid will be as follows:-

=0.1*0.05

=0.005 Moles

mass of sulfuric acid = 0.005*98 g =  0.49 grams

1 gram = 1000 milli gram

so,

mass of sulfuric acid given = 0.49*1000 = 490 grams

now,

we know that:-

milliEquivalents = mass(in milligram)*valance factor/molar mass

The Valency Factor for Sulfuric acid is 2 as there are 2 atoms of replaceable Hydrogen present in Sulfuric Acid.

mEq = 490*2/98

mEq= 10 milli equivalents