Question

Calculate number of molecules and moles of acetic acid present in 22g

Answer 1

Answer:

mole=2.72

Explanation:

Ch3cooh=12+3+12+16+16+1=60

in 60 gram of ch3cooh contain

1 mole

so,in 22g of ch3cooh= 22/60 mole= 2.72 mole

in 1mole of co2 contain 6.022×10^23 molecule

so,in 2.72 mole------6.022×10^23x2.72

molecule