calculate number of molecules of sulphur (S8) present in 128g of sulphur
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For that let us first write the values given in the question-$mass = 128g$, the molecular mass of \[{S_8}\]=$8 \times 32g = 256g$. Therefore, the number of molecules of Sulphur (\[{S_8}\]) is $3.011 \times {10^{23}}$.
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Explanation:
Moles = mass/molecular mass , molecular mass of sulphur(S8) = 32x8=256g
128/256=0.5
molecules = moles x avogadro no. =0.5 x 6.022 x 10^23=3.011 x 10^23
=3.011 x 10^23
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