Question

calculate number of molecules present in 180gm of CH3COOH​

Answer 1

Mass of CH3COOH present=180g

Molar mass of CH3COOH=160g

Number of moles present=180/160=9/8mol

In 1 mol, there are 6.022 x 10²³ molecules

in 9/8mol, there will be 9/8 x 6.022 x 10²³ molecules

So number of molecules present are=6.77 x 10²³