calculate number of molecules present in 180gm of CH3COOH
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Mass of CH3COOH present=180g
Molar mass of CH3COOH=160g
Number of moles present=180/160=9/8mol
In 1 mol, there are 6.022 x 10²³ molecules
in 9/8mol, there will be 9/8 x 6.022 x 10²³ molecules
So number of molecules present are=6.77 x 10²³
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