Question

calculate number of molecules present in one litre of water assuming that the density of water is 1g/cm³.​

Answer 1

Explanation:

Answer. One mole of water has a mass of 18 grams and a volume of 18 mL (as the density of water is 1 g per cm3). It contains Avogadro's number of molecules (6x 10^23). Thus 1 litre of water contains 1 / 18 x 1000 x 6 x 1^23.

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Answer 2

Given :

• Density of water = 1g/cm³

To Find :

• Number of molecules in one litre of water

Solution :

As, we know that 1 mole of water = 18 g

Now, Mass of 1 litre of water = Volume × Density

= 1000 mL × 1g/mL

= 1000 g

Now, 18 g of water contains 6.022 × 10²³ molecules.

Hence, 1000 g (1 litre) of water will contain = $\sf \dfrac{6.022 \times 10^{23} \times 1000}{18}$

= 3.346 × 10²⁵ molecules.

Hence, 1 litre of water will contain 3.346 × 10²⁵ molecules.