calculate number of moles and molecules of ammonia present in 5.6dm of its volume
Answers
Answered by
0
Answer:
Solution:
No. of moles=
22.4
vol
=
22.4
5.6
=0.25 moles
No of molecules=Avogadro no×no. of moles
=6.023×10
23
×0.25
=1.50575×10
23
Explanation:
Answered by
1
ANSWER
Solution:
No. of moles=
22.4
vol
=
22.4
5.6
=0.25 moles
No of molecules=Avogadro no×no. of moles
=6.023×10
23
×0.25
=1.50575×10
Solution:
No. of moles=
22.4
vol
=
22.4
5.6
=0.25 moles
No of molecules=Avogadro no×no. of moles
=6.023×10
23
×0.25
=1.50575×10
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