Question

calculate number of moles and molecules present in 8.8 gram of carbon dioxide also calculate the number of oxygen atoms present in this
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Answer 1

Answer:

The number of moles = 0.2 moles.

The number of molecules =  1.2044×10²³

The number of oxygen atoms = 2.4088×10²³

Explanation:

Here we have 8.8 grams of carbon dioxide.

We know that,

The atomic mass of carbon = 12$g/mol$

The atomic mass of oxygen = 16$g/mol$

From the above,

The molar mass of carbon dioxide = 44$g/mol$

∴Number moles of carbon dioxide present = $\frac{8.8}{44}$= 0.2 moles.

The number of molecules present in one mole = 6.022×10²³

in 0.2 moles number of molecules of carbon dioxide = 0.2× 6.022×10²³

                                                                                     = 1.2044×10²³

The number of oxygen atoms in one molecule of carbon dioxide = 2

∴ the number of oxygen atoms in 8.8 grams of CO₂= 1.2044×10²³×2

                                                                                     = 2.4088×10²³

Answer 2

Answer:

The number of moles of carbon dioxide is 0.2 moles

The number of molecules present in 8.8 grams of carbon dioxide is 1.2044×$10^{23}$ molecules

The number of oxygen atoms present in 8.8 grams of carbon dioxide is 2.4088× $10^{23}$ atoms.

Explanation:

We know that the molecular formula of carbon dioxide is  $CO_{2}$ .

So the molecular weight of carbon dioxide is 44 g/mol

The given weight of carbon dioxide is 8.8 grams.

The number of moles of carbon dioxide

                                           = given weight of $CO_{2}$ ÷ molecular weight of

                                           = $\frac{8.8}{44} = 0.2 moles$

The number of moles present in one mole of carbon dioxide is $6.022*10^{23}$

The number of molecules present in 0.2 moles of carbon dioxide

                                            = $6.022*10^{23}$ × 0.2 = 1.2044 × $10^{23}$ molecules

Two oxygen atoms are present in one molecule of carbon dioxide

therefore, the number of oxygen atoms present in 8.8 grams of carbon dioxide = 2× 1.2044 × $10^{23}$ = 2.4088× $10^{23}$ atoms.