Question

calculate number of moles present in 12.044*10^23 atoms of the 'He'.
Atomic mass of 'He' is 4u
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Answer 1

Answer:

For Helium,

Number of atoms=Number of moles ×6.022×10  

23

 

No of Moles =  

6.022×10  

23

 

12.044×10  

23

 

​  

 = 2.

Now, atomic mass of He=4

Weight = 2×4 = 8 g

Explanation: