calculate number of moles present in 3.011 × 10²²atom of H2O
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Answered by
4
1mole equal to 6.23*10²³ atom
lets there are n mole so
n*6.022*10²³=3.011*10²²
n=3.011*10²²/6.022*10²³
=1/20
0.05 moles
lets there are n mole so
n*6.022*10²³=3.011*10²²
n=3.011*10²²/6.022*10²³
=1/20
0.05 moles
Answered by
2
Molar mass of H20 = 18g
And in 18 g there is 1 mole = 6.022 x 10 ²³ atoms
1mole = 6.022 x 10²³
1/6.022 x 10 ²³ = 1 atom
1x 3.011 x 10²²/ 6.022 x 10²³ = 3.011 x 10²² atoms
1/20 = 3.011 x 10²² atoms
0.05 moles = 3.011 x 10²²atoms
And in 18 g there is 1 mole = 6.022 x 10 ²³ atoms
1mole = 6.022 x 10²³
1/6.022 x 10 ²³ = 1 atom
1x 3.011 x 10²²/ 6.022 x 10²³ = 3.011 x 10²² atoms
1/20 = 3.011 x 10²² atoms
0.05 moles = 3.011 x 10²²atoms
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