Question

calculate number of moles present in 5g of so3​

Answer 1

Answer:0.0625 moles

Explanation:

1 mole contains 80g of SO3[S=32g,O3=16*3=48g ;32+48=80]  

so 5g of SO# contains=5/80=0.0625 moles

Answer 2

Answer: 0.025 moles

Explanation:

Total atomic mass  = 32+48 = 80

80g of $SO_{3}$ = 1 mole of $SO_{3}$

5g = $\frac{5}{80}$ moles

= 0.0625 moles