Question

calculate number of neutrons present in 200L Co2 gas at 0.821 atm pressure and 727℃ temperature . ​

Answer 1

Answer: The number of neutrons in given amount of carbon dioxide gas is $2.64968\times 10^{25}$

Explanation:

To calculate the total number of moles, we use the equation given by ideal gas, which is:

$PV=nRT$

P = pressure = 0.821 atm

V = volume = 200 L

n = number of moles = ?

R = Gas constant = $0.0820\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $727^oC=[727+273]=1000K$

Putting values in above equation, we get:

$0.821atm\times 200L=n\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 1000K\\\\n=2.00mol$

Number of neutrons in Carbon = 6

Number of neutrons in oxygen = 8

Number of neutrons that are present in 1 mole of carbon dioxide gas = [6 + 8 + 8] = 22

According to mole concept:

1 mole of an compound contains $6.022\times 10^{23}$ number of molecules or electrons or protons or neutrons.

So, 2 moles of carbon dioxide gas will contain = $22\times 2\times 6.022\times 10^{23}=2.64968\times 10^{25}$ number of neutrons.

Hence, the number of neutrons in given amount of carbon dioxide gas is $2.64968\times 10^{25}$