Question

Calculate number of o2 molecules which occupy 22.7 CM cube at STP

Answer 1

Answer:

22400 ml. of oxygen at 273 K temperature and 3-atm pressure = 22400 ×3/1= 67200 ml at STP.

So 224 ml of oxygen at 273 K and 3-atm = 224 ×3= 672 ml at STP

The number of Oxygen molecules present in 22400 ml of gas at STP=N

(where N= Avagadro Number)

Therefore 224 ml of oxygen at 273K and 3-atm pressure will contain =N×672/22400 × N molecules.

=3/100×6.022×10

23=18.066×10

21

Molecules =1.8066×10

22molecules