Question

calculate number of oxygen and carbon atom present in 360 gram of glucose? ​

Answer 1

Answer:

Glucose⟶C

6

H

12

O

6

Number of moles=

molecular mass

mass

=

180

1.8

=0.01 mol

Now, there are 6 atoms of oxygen

Total number of oxygen atoms=number of atoms of oxygen×number of moles×Avagadro's constant

=6×0.01×6.023×10

23

=36.138×10

21