Question

calculate number of particle of. 92gm of Na

Answer 1

m = 92gm
M = 23

Moles = m / M

= 92 / 23

= 4 moles

So no. Of particles are 4 * 6.022*10^23

= 2.4 * 10^24 particles

THANKS

Answer 2

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UR ANS...

$Given$:
mass of Na=0.92gm

$To \: find$: number of particles 0.92 gram of Na

$Sol {}^{n}$:
we know atomic mass of sodium is 23u
hence its molar mass will be 23g/mol
here we will apply the formula,
$n = N\div N_{o}$
we need to find N.
hence the formula will become,
$N = n \times N_{o}$

$= 23 \times (6.022 \times {10}^{23} )$

$= 138.506 \times {10}^{23} is \: your \: answer$
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