calculate number of particles and number of moles in 100 kg of CH3CH2CH2OH
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Molecular weight of CH3CH2CH2OH = 12(3) + 1(8) + 1(16) = 60
No.of moles of compound present=Weight of the given compound/Molecularwt
Therefore no. of moles of the given compound = 100 x1000 grams/ 60
= 1666.6 moles of CH3CH2CH2OH
One mole of any compound has avagadro number of particles (N)
Where N = 6.023 x 10^23
1666.6 moles of the compound contains 166.6N no. of particles
= 1666.6 x 6.023 x 10^23
No.of moles of compound present=Weight of the given compound/Molecularwt
Therefore no. of moles of the given compound = 100 x1000 grams/ 60
= 1666.6 moles of CH3CH2CH2OH
One mole of any compound has avagadro number of particles (N)
Where N = 6.023 x 10^23
1666.6 moles of the compound contains 166.6N no. of particles
= 1666.6 x 6.023 x 10^23
ujjwal126:
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