Question

Calculate number of particles in 31 grams of phosphorus molecules.​

Answer 1

Explanation:

Data :

Weight of given phosphorus =31grams

Molecular weight of phosphorus =30. 97 ~31gram/mole.

$n = weight + \div moleular \: weight \\ n = 31 \div 31 = 1mole$

N=n×avagadro no.

$= 1 \times 6.022 \times 10 ^{ 23} \\ = 6.022 \times 10 ^{ 23}$

No. Of phosphorus molecule 31 grams of mass is 6. 022×10^23

Answer 2

Answer:

Data :

Weight of given phosphorus =31grams

Molecular weight of phosphorus =30. 97 ~31gram/mole.

\begin{lgathered}n = weight + \div moleular \: weight \\ n = 31 \div 31 = 1mole\end{lgathered}

n=weight+÷moleularweight

n=31÷31=1mole

N=n×avagadro no.

\begin{lgathered}= 1 \times 6.022 \times 10 ^{ 23} \\ = 6.022 \times 10 ^{ 23}\end{lgathered}

=1×6.022×10

23

=6.022×10

23

No. Of phosphorus molecule 31 grams of mass is 6. 022×10^23