Calculate number of particles in 52g of Helium
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The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g. Hence 1 mole of He = 4 g of He = 6.022 X 1023atoms of He.
1 g of He = (6.022 X 1023) / 4 atoms of He.
52 g of He = (6.022 X 1023X 52 ) / 4 atoms of He.
1 g of He = (6.022 X 1023) / 4 atoms of He.
52 g of He = (6.022 X 1023X 52 ) / 4 atoms of He.
Answered by
1
The molar mass that is the mass of 6.022×1023 atoms of helium is 4 g. Hence 1 mole of He =4 g of He=(6.022×1023)/4 atoms of He.
52 g of He =(6.022×1023×52)/4 atoms of He.
52 g of He =(6.022×1023×52)/4 atoms of He.
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