Question

calculate number of photon of light of lambda 4000 A° which provide 1 joule of energy . (2×10^18)​

Answer 1

Answer:

The wavelength of light is 4000pm or 4000×10 ^−12

m or 4000×10 ^−9 m.

The energy one photon is λhc

= 4×10 −9

6.626×10

−34 ×3×10 ^8

=4.97×10^ −17

.

The number of photons that will provide 1 J of energy is

4.97×10

−171j

J=2.01×10^ 18

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Answer 2

Answer:

2.01×10^18

Explanation:

I hope this is helpful for you