Question

calculate number of photons emitted in 10 seconds by a 100W bulb if wavelength of light is 3000A​

Answer 1

Explanation:

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Answer 2

The number of photons is 150.8 × 10^19 photons.

Given:

The photons are emitted in 10 seconds by a 100W bulb if the wavelength of light is 3000A.

To Find:

The number of photons.

Solution:

To find the number of photons we will follow the following steps:

As we know,

$Power = \frac{energy}{time}$

So, the total energy emitted by a 100W bulb is:

$energy = power \times time = 100 \times 10 = 1000joule$

Now,

The energy emitted by 1 photon is calculated by the formula:

$\frac{hc}{d}$

Here, h is Planck's constant c is the speed of light and d is the wavelength.

h = 6.63× 10^-34 s.

c = 3 × 10^8 ms-1

d = 3000A° = 3000 × 10^-10 = 3 × 10-7 metres.

Now,

The energy of 1 photon =

$\frac{6.63 \times 3 \times {10 }^{ - 34} \times {10}^{8} }{3 \times {10}^{ - 7} }$

$\frac{6.63}{1} \times {10}^{ - 34 + 8 + 7} = \frac{6.63}{1} \times {10}^{ - 19}joule$

Now,

Number of photons =

$\frac{energy \: of \: total \: phoons}{energy \: of \: 1 \: photon} = \frac{1000}{6.63 \times {10}^{ - 19} } =$

= 150.8 × 10^19.

Henceforth, the number of photons is 150.8 × 10^19.

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