Question

calculate number ofunit cells in 0.3g ofa species having density of 8.5 g/cm^3 and unit cell edge length 3.25*10^-8cm

Answer 1

We have to calculate the number of unit cells in 0.3g of a species having density of 8.5 g/cm³ and unit cell edge length is 3.25 × 10^-8 cm.

solution : volume of a unit cell = (edge length)³

= (3.25 × 10^-8 cm)³

= 3.433 × 10¯²³ cm³

mass of a unit cell = density × volume of a unit cell

⇒mass of a unit cell = 8.5 g/cm³ × 3.433 × 10¯²³ cm³ = 29.18 × 10¯²³ g ≈ 0.3 × 10¯²¹ g

now number of unit cells = given mass/mass of a unit cell

= 0.3g/(0.3 × 10¯²¹ g)

= 10²¹

Therefore the number of unit cells is 10²¹.

also read similar questions : an element atomic mass 50 having fcc structure has a density of 5.7 g/cm^3. What is the edge length of the unit cell?

https://brainly.in/question/28569419

silver crystallize in fcc lattice. if edge length of the cell is 4.07×10^8 CM and density is 10.5 g cm^3,calculate the a...

https://brainly.in/question/4258805