Calculate numbers of atom in 0.85gram in ammonia??
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The answer is: (3.011×10^22) NH3 molecules are present in 0.85 g ammonia. But you haven't cleared the name of atom.
The number of N atoms= 3.011×10^22
The number of H atoms=3×3.011×10^22=9.011×10^22
The total number of atoms=4×3.011×10^22=12.044×10^22
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