Calculate numericaly what is the moment of inertia of a solid sphere of density ¶ and radius R about its diameter
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Contrary to the opinions of others, I believe the rationale behind the derivation of the I=2/5MR2 formula is far more important than the formula itself. The radius of the sphere is R. Let is conceive of a disk of radius r located at a distance x from the center of the sphere. For purposes of calculation herein, let us state its thickness to be dx. r=R2−x2−−−−−−−√ The volume of this disk is thus: dV=πr2dx=π(R2−x2)dx The mass of this disk is: dm=ρdV=πρ(R2−x2)dx We know that, over a uniform body: I=∫r2dm Therefore, I=∫r2(πρ(R2−x2)dx =πρ∫R0(R2−x2)2dx Carrying out the integration, we obtain: I=8πρ15R5 And since M=ρV=4πρR33 Substituting the given value for ρ I=2/5MR2
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