Question

Calculate of the area of the triangle whose sides are 20 cm, 21cm,29 cm.Hence, find the length of the altitude corresponding to the largest side.

Answer 1

here we use heron's formula
area=
$\sqrt{p(p - a)(p - b)(p - c)}$
where a,b,c are the sides of triangle
here we need to find p which is equal to
$\frac{a + b + c}{2}$
p=35
Therefore area of triangle=√35(35-20)(35-21)(35-29)=√35×15×14×6=√44100=210

Answer 2

Given :  triangle whose sides are 20 cm, 21cm, 29 cm  

To Find :  the length of the altitude corresponding to the largest side

Solution:

Sides are

20 cm

21 cm

29 cm

20² + 21²

= 400 + 441

= 841

= 29²

Hence given triangle is right angle triangle

Area of triangle = (1/2) * 20 * 21   = 210  cm²

Area of triangle = (1/2) * 29 *  altitude corresponding to the largest side.

=> 210 = (1/2) * 29 *  altitude corresponding to the largest side.

=>  altitude corresponding to the largest side. = 420/29 cm

= 14.483 cm

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