Math, asked by vippandian6827, 1 year ago

Calculate of the area of the triangle whose sides are 20 cm, 21cm,29 cm.Hence, find the length of the altitude corresponding to the largest side.

Answers

Answered by saumya120
24
here we use heron's formula
area=
 \sqrt{p(p - a)(p - b)(p - c)}
where a,b,c are the sides of triangle
here we need to find p which is equal to
 \frac{a + b + c}{2}
p=35
Therefore area of triangle=√35(35-20)(35-21)(35-29)=√35×15×14×6=√44100=210
Answered by amitnrw
7

Given :  triangle whose sides are 20 cm, 21cm, 29 cm  

To Find :  the length of the altitude corresponding to the largest side

Solution:

Sides are

20 cm

21 cm

29 cm

20² + 21²

= 400 + 441

= 841

= 29²

Hence given triangle is right angle triangle

Area of triangle = (1/2) * 20 * 21   = 210  cm²

Area of triangle = (1/2) * 29 *  altitude corresponding to the largest side.

=> 210 = (1/2) * 29 *  altitude corresponding to the largest side.

=>  altitude corresponding to the largest side. = 420/29 cm

= 14.483 cm

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