Calculate of the area of the triangle whose sides are 20 cm, 21cm,29 cm.Hence, find the length of the altitude corresponding to the largest side.
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Answered by
24
here we use heron's formula
area=
where a,b,c are the sides of triangle
here we need to find p which is equal to
p=35
Therefore area of triangle=√35(35-20)(35-21)(35-29)=√35×15×14×6=√44100=210
area=
where a,b,c are the sides of triangle
here we need to find p which is equal to
p=35
Therefore area of triangle=√35(35-20)(35-21)(35-29)=√35×15×14×6=√44100=210
Answered by
7
Given : triangle whose sides are 20 cm, 21cm, 29 cm
To Find : the length of the altitude corresponding to the largest side
Solution:
Sides are
20 cm
21 cm
29 cm
20² + 21²
= 400 + 441
= 841
= 29²
Hence given triangle is right angle triangle
Area of triangle = (1/2) * 20 * 21 = 210 cm²
Area of triangle = (1/2) * 29 * altitude corresponding to the largest side.
=> 210 = (1/2) * 29 * altitude corresponding to the largest side.
=> altitude corresponding to the largest side. = 420/29 cm
= 14.483 cm
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