Question

calculate of total energy of an electron in a bohr orbit​

Answer 1

Answer:

Explanation:

In the Bohr's Orbit,

Potential Energy = 2(Total Energy)

And Kinetic Energy = -(Total Energy)

Hence, PE=2(-1.5)= -3.0 ev.

Also KE= -(-1.5)= 1.5 ev. ...

1/wavelength= RH(Z)2 [1/n12-1/n22]

Or simply, Wavelength(nm)= 1240/Energy difference between the two orbits(ev).

= 102.4 nm

Answer 2

Explanation:

HEY MATE

HERE IS YOUR ANSWER

AS TOTAL ENERGY =KINETIC+potential energy

E=K.. E+P. E

ALSO

HERE

Q1=Ze

Q2=e

K. E = KQ1Q2/2R (according to electrostatic)

k.e =kze²/2r

p. e = - kq1q2/r

p.e =-kze²/r

so total energy will be

t.e=kze²/2r + (- kze²/r)

T.E. = -KZE²/2R

THIS IS YOUR FINAL RESULT

BUT ACCORDING TO PAPER

THEY ASK THE RELATION BY P.E K.E T

E

T.E= -K.E =P.E/2

HOPE IT WILL HELP YOU

THANKS