Calculate or derive the formula for average acceleration of a projectile on an inclined plane .
Given : inclination of plane is ¢ and angle of projection $ , the initial velocity of projection is u .
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Answer:
Given : u=10 m/s
Initial velocity along x direction u
x
=ucos30
o
m/s
Initial velocity along y direction u
y
=usin30
o
m/s
Also acceleration x and y direction a
x
=−gsin30
o
m/s
2
and a
y
=−gcos30
o
m/s
2
x direction : V
x
=u
x
+a
x
t
time t=
10cos30
2×10sin30
, hence t=
3
2
s
∴ V
x
=ucos30
o
−(gsin30
o
)t
OR V
x
=10×
2
3
−10×0.5×
3
2
=
3
15−10
=
3
5
m/s
Also V
y
=−5 m/s (solved earlier)
∴ Speed of the particle at collision V=
V
x
2
+V
y
2
=
(
3
5
)
2
+(−5)
2
⟹ V=
3
100
=
3
10
m/s
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