calculate Osmotic pressure of the solution which contains 68.4 gram sucrose in 1000 ml of solution at 293 k R 0.082
Answers
Answered by
10
PV=nRT
=0.15*0.082*293
= 3.6 Pa
=0.15*0.082*293
= 3.6 Pa
Similar questions
Hindi,
8 months ago
Math,
8 months ago
Math,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago