Question

calculate oxidation no. of N in (NH4)2SO4

Answer 1

Hope this helps with your question.

Answer 2

Answer:

The answer is -3

Explanation:

(NH4)2SO4..,

Let N ox.no. be x.

2 [x + 4 × 1] + 6 + 4 × (-2).

= 2x + 8 + 6 - 8.

2x + 6 = 0.

2x=-6.

X=-3.

Thus ,oxidation state of N in this is "-3."

Simply put, an element's oxidation number is the number assigned to it in a chemical combination. The number of electrons that atoms in a molecule can share, lose, or gain while forming chemical connections with other atoms of a different element is known as the oxidation number.

Oxidation state is another name for oxidation number. However, depending on whether or not we are taking into account the electronegativity of the atoms, these phrases might occasionally have a different meaning. In coordination chemistry, the phrase "oxidation number" is commonly employed. The transfer of electrons can generally be described in terms of oxidation status or number. Students should be aware that this is not the same as a formal charge, which controls atom configuration.

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