Question

Calculate oxidation no. of s in (nh4)2so4

Answer 1

Answer:

Oxidation no of n = -3

Oxidation no of h = 1

Oxidation no of s = x

Oxidation no of o = -2

Therefore, -3×2 + 1×4×2 + x + -2×4 = 0

-6+8+x-8 = 0

x-6 = 0

x = 6

Oxidation no. of s in (NH4)2SO4 is +6