Question

Calculate oxidation number of CH2so5

Answer 1

CH2SO5
Oxidation number of C is +4 , H is +1 , S is -2 ,
O is -2
therefore
Oxidation number of CH2SO5 IS
=(+4)+(1 )×2+(-2)+(-2)×5
=-6

Answer 2

Answer:

+ 4

Explanation:

Given :

Compound CH₂SO₅

We have to calculate oxidation number of S in CH₂SO₅ .

We know :

O.N. of C = + 4

O.N. of H = + 1

O.N. of 0 = - 2 .

Let O.N. of S be y :

4 + 2 × 1 + y - 2 × 5 = 0  [ Net charge is 0 ]

4 + 2 + y - 10 = 0

y + 6 - 10 = 0

y - 4 = 0

y = + 4 .

Hence oxidation number of S is + 4 in CH₂SO₅ .