Question

Calculate oxidation number of following compound 1. CrO3
2.H2SO4

Answer 1

Explanation:

Hydrogen, H, has an oxidation number of +1. Oxygen, O, has an oxidation number of -2. Since it is a neutral compound, the sulfur atom must have an oxidation number of +6. And The most common oxidation states of chromium are +6, +3, and +2. A few stable compounds of the +5, +4, and +1 states, however, are known. In the +6 oxidation state, the most important species formed by chromium are the chromate, CrO42−, and dichromate, Cr2O72−, ions.