Calculate oxidation number of S in (S406)2-
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Let oxidation number of s be x. Oxidation no. ...
The algebraic sum of oxidation no. ...
Therefore,
(4×x) +(–2×6) =–2.
4x–12 = –2.
4x = –2+12.
4x = +10.
X= +10/4.
Hope it helps uh...
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