Chemistry, asked by khunlawrence37, 6 months ago

Calculate oxidation number of S in (S406)2-​

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Answered by Anonymous
1

Answer:

Let oxidation number of s be x. Oxidation no. ...

The algebraic sum of oxidation no. ...

Therefore,

(4×x) +(–2×6) =–2.

4x–12 = –2.

4x = –2+12.

4x = +10.

X= +10/4.

Hope it helps uh...

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