Calculate oxidation number of the following components
(l) Mn in K2MnO4
(ll) Ca in CaOCI2
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Answer:
let oxidation state of Mn be x.
As we know, the oxidation state of O is -2 and that of H is +1.
K
2
MnO
4
:2+x+(−8)=0
⇒x=8−2
⇒x=+6.
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