Calculate oxidation number on Br in BrO2-
Answers
Answer:
In (BrO2)-
let the oxidation number of Br be x
then we know the oxidation number of O which is -2
then x+2(-2)=-1
x=3.
Explanation:
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Answer:
How to calculate Oxidation Number?
To calculate oxidation number we need to understand and follow certain rules. There are six rules:
Each atom in an element either in its free or uncombined state holds up an oxidation number of zero. Clearly, each atom in H2, Cl2, P4, Na, Al, O2, O3, S8, and Mg, has an oxidation number zero.
The oxidation number of ions which comprise of only one atom is equal to the actual charge on the ion.
In most of the compounds, the oxidation number of oxygen is –2. There are two exceptions here.
Peroxides- Every oxygen atom is allocated an oxidation number of –1. Example, Na2O2
Superoxides- Every oxygen atom is allocated an oxidation number of –(1/2). Example, KO2
Oxygen is bonded to fluorine- Example, dioxygen difluoride where the oxygen atom is allocated an oxidation number of +1.
Hydrogen’s oxidation number is +1, excluding when it is bonded to metals containing two elements. For example, CaH2, its oxidation number equals to –1.
Fluorine and other halogens have an oxidation number –1 when they appear as halide ions in their compounds. When iodine, chlorine, and bromine are combined with oxygen, their oxidation number is positive.
When the oxidation number of the atoms of a compound are added together the algebraic sum must be equal to zero. In case of polyatomic ion, when the oxidation number of the atoms of an ion are added together the algebraic sum must be equal to the charge on the ion. Consider (CO3)2– the algebraic sum of oxidation number of one carbon atom and three oxygen atom is equal to -2.
Learn more about how to calculate oxidation number along with the steps.
Read more:
Oxidation and reduction
Oxidizing agent
Difference between oxidation and reduction
Explanation:
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