Question

calculate oxygen atoms present in 8.8g co2 molecule

Answer 1

Answer:

Given:

8.8 g of carbondioxide = moles of carbondioxide.

To find:

Number of O2 atom in CO2.

Explanation:

Molar mass of CO2:

$12 + 16 \times 2 = 44g$

44 g CO2 having 1 mol of O2 and 1 mol of CO2 having 2 mol of O2.

Then, 88 g of CO2 having 2 mol of O2 and 2 mol of CO2 having 4 mol of O2.

So, the number of atoms can be counted by

number of atoms = no. of moles x Avogadro's number

$4 \times 6.023 \times10 ^{23}$

$= 24.092\times 10^{23}$

so. the number of oxygen atoms are $= 24.092\times 10^{23}$

Answer 2

Answer:

no of mole = mass given/ molar mass

8.8/44

= 0.2 mol

so 1 molecule of co2 contain 2 atoms of o2

then 1 mole of co2 contain 2 mole of o2

so 0.2 mole of co2 contain 2×0.2=0.4 mole of o2

answer is 0.4 mole of o2

no. of oxygen atom present in o2= mole of o2 × avagadro no.

so mole is 0.4

and value of avagadro no.=6.022×10-²³

put the value in formula

then 0.4×6.022×10-²³ = 2.4×10-²³ atoms of o2.

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